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Archimedes' Principle

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1. A copper penny has a mass of 2.7 g. What is the buoyant force acting on this penny when dropped into water? (The answer should be 3.0 mN)

2. An iceberg (917 kg/m^3) is floating in the ocean (1,025 kg/m^3). What percentage of the total volume of the iceberg is below the surface of the water? (The answer should be 89.5%)

https://brainmass.com/physics/gravity/archimedes-principle-511735

SOLUTION This solution is FREE courtesy of BrainMass!

1. The buoyent force acting on the penny is equal to the weight of water displaced by the penny. Since copper has a specific gravity of S = 9.0, the mass of water displaced by the penny is

m_w = m_p/S
= 2.7 g / 9.0
= 0.3 g.

Thus, the buoyancy of the penny is

F_b = m_w g
= (0.3 g) (9.8 m/s^2)
= 2.9 g m/s^2
= 2.9 mN.

2. The mass of water displaced by the iceberg is equal to the total mass of the iceberg. Thus we have

m_w = m_i
d_w V_w = d_i V_i

V_w/V_i = d_i/d_w
= (917 kg/m^3)/(1,025 kg/m^3)
= 0.895.
= 89.5%.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!