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Archimedes principle

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A rectangular block of height L and horizontal cross-sectional area A floats at the interface between two immiscible liquids, as shown in the picture (attached).

a) Derive a formula for the block density in terms of the fluid densities, P1 and P2, the heights h0, h1, and h2 and the cross-sectional area A. (it is not necessary that all of these variables appear in the final result.)

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The problem is solved using Archimedes principle.

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Liquid 1 density ρ1 g/cc


Block density ρb g/cc
L h2

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