Archimedes principle
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A rectangular block of height L and horizontal cross-sectional area A floats at the interface between two immiscible liquids, as shown in the picture (attached).
a) Derive a formula for the block density in terms of the fluid densities, P1 and P2, the heights h0, h1, and h2 and the cross-sectional area A. (it is not necessary that all of these variables appear in the final result.)
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Solution Summary
The problem is solved using Archimedes principle.
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SOLUTION
Liquid 1 density ρ1 g/cc
h0
h1
Block density ρb g/cc
L h2
...
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