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Newton's Laws of Motion

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The two forces P applied horizontally to the bottom of the symmetrical frame control the vertical motion of the 60 kg cylinder. Determine the constant force P which, if applied when the frame is at rest with B = 120 degrees, will give the cylinder an upward velocity of 3 m/s when the position of B is 60 degrees is passed.

The links are very light and their mass may be ignored and are all .6 m in length (.3 meters between connections).

For the instant when the upward acceleration id 20 m/s what is the force R under each of the supporting rollers.

(Please refer attachment for fig.)

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Solution Preview

Please refer to the attachment.

Fundamental principle : Part of the total work done by the forces P goes to increase the potential energy of mass m. Balance of the work done (if any) manifests as the kinetic energy of the mass. Hence,

Work done by the forces P = Increase in PE of mass m + KE ...

Solution Summary

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