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    Impulse and force: a ball drops vertically onto a floor

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    A 1.2 kg ball drops vertically onto a floor, hitting with a speed of 25 m/s. It rebounds with an initial speed of 10 m/s.
    (a) What impulse acts on the ball during the contact?
    (b) If the ball is in contact with the floor for 0.020 s, what is the magnitude of the average force on the floor from the ball?

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    Solution Preview

    (a) Impulse on the ball = change in momentum for the ball = 1.2 kg * (10 - (-25)) m/s = ...

    Solution Summary

    Solution is straightforward application of formulas.