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Forces Acting on an Object

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Three forces acting on an object are given by F1 = (−1.85 i + 7.35 j) N, F2 = (4.70 i − 1.15 j) N, and F3 = (−45.5 i) N. The object experiences an acceleration of magnitude 3.70 m/s2.
(a) What is the direction of the acceleration?
(degrees counterclockwise from the positive x axis)
(b) What is the mass of the object in kg?
(c) If the object is initially at rest, what is its speed after 16.0 s in m/s?
(d) What are the velocity components of the object after 16.0 s in m/s?

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Solution Summary

Effect of 3 forces acting on an object is described: acceleration, velocity (magnitude and direction).

Solution Preview

F1 = (-1.85 i + 7.35 j) N,
F2 = (4.70 i - 1.15 j) N,
F3 = (-45.5 i) N.

Net force,
Fnet = F1 + F2 + F3
= (-1.85 i + 7.35 j) + (4.70 i - 1.15 j) + (-45.5 i)
= (-1.85 + 4.70 - 45.5)i + (7.35 - 1.15)j

Solution provided by:
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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