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Dragging box on the floor

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Part 1. If I had a box with a mass (m) and dragged it across a level floor having a coefficient of kinetic friction uk by a rope that is being pulled upward at an angle (the symbol 0 with a one through it ) above the horizontal with a force of magnitude (F). In terms of M, uk, the symbol 0 with a line through it,l and g what would be an expression for the magnitude of force required to move my box at a constant speed?

Part 2. How much force would it take to slide my 90-kg brother across the floor at a constant speed by pulling him at ab angle of 25% above the horizontal. Next by dragging some weights wrapped in an old pair of his pants down the hall with a spring balance I find that uk +0.35. I want to use the result of part one to answer part two.

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Solution Preview

Please see the attached file.

Use the diagram above to understand better,
f represents the frictional force which is:
f=uk*Mg , ...

Solution Summary

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Coefficient of Friction: Acceleration Change

A box of mass 12 kg is placed in the back of a van. The coefficient of friction between the box and the floor is 0.6. What happens to the box if the lorry moves off with an acceleration of:

(a) 4 ms^2
(b) 6 ms^2
(c) 8 ms^2

(Take g = 10 ms^-2)

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