Show that none of the principal moments of inertia can exceed the sum of the other two.
Answer is as follows:
For a rigid body of N point-masses mi, the moment of inertia with respect to the principal axes are given by:
Ixx = Sum (yi^2 + zi^2)
Iyy = Sum (xi^2 + zi^2)
Izz = Sum (xi^2 + yi^2)
Where Sum means ...
Proof to this question is provided in a clear step-by step manner.