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    Physical pendulums

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    A thin uniform ring, placed on a knife edge pivot executes SHM period 'Tr'.
    The same ring is cut, then straightened to form a bar, which executes SHM with a period 'Tb'.
    Find the ratio of periods, Tb/Tr.

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    Solution Preview

    Step1. Recall moments of inertia as follows:
    Thin uniform ring about its c.m. axis (at center): (1) Io ...

    Solution Summary

    The expert compares the period of ring to that of bar.