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Moments of Inertia

Show that none of the principal moments of inertia can exceed the sum of the other two.

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Answer is as follows:

For a rigid body of N point-masses mi, the moment of inertia with respect to the principal axes are given by:

Ixx = Sum (yi^2 + zi^2)

Iyy = Sum (xi^2 + zi^2)

Izz = Sum (xi^2 + yi^2)

Where Sum means ...

Solution Summary

Proof to this question is provided in a clear step-by step manner.