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The Refraction of Perpendicularly Incident White Light

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The refraction of perpendicularly incident white light by a soap film in air has an interface maximum at 600nm and a minimum at 450nm, with no minimum in between. If n=1.33 for the film, what is the film thickness, assumed uniform?

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The solution works through the problem step by step to clearly arrive at the answer detailing the necessary thickness of soap film to produce the described ray of white light.

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For interference maxima by a soap film of thickness t is given as,
2*n*t = (k+(1/2))*lambda_1 ...(1)
where, n= refrective index of film = 1.33
lambda_1 = wavelegth for which there is maxima = 600 nm
k = an integer

For minima with a ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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