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    The Refraction of Perpendicularly Incident White Light

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    The refraction of perpendicularly incident white light by a soap film in air has an interface maximum at 600nm and a minimum at 450nm, with no minimum in between. If n=1.33 for the film, what is the film thickness, assumed uniform?

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    For interference maxima by a soap film of thickness t is given as,
    2*n*t = (k+(1/2))*lambda_1 ...(1)
    where, n= refrective index of film = 1.33
    lambda_1 = wavelegth for which there is maxima = 600 nm
    k = an integer

    For minima with a ...

    Solution Summary

    The solution works through the problem step by step to clearly arrive at the answer detailing the necessary thickness of soap film to produce the described ray of white light.