A beam of light of wavelength 550nm, traveling in air, is incident on a slab of transparent material. The incident beam makes an angle of 40 degrees with the normal, and the refracted beam makes an angle of 26 degrees with the normal.
(a) Find the index of refraction on the material?
(b) What is the wavelength of this light in the slab?
Since n1*Sin(theta1)=n2*Sin(theta2), where n1 and n2 are the index of refraction of materials and theta1 ...
The solution utilises the relevant formulae to quickly and concisely find the index of refraction and wavelength of a refracted beam of light.