# Magnification of the Image Formed by the Lens

An object is placed to the left of a convex lens and on the optical axis. The object is 36 cm from the lens and the focal length of the lens is 66 cm. What is the magnification of the image formed by the lens? You do not have to enter units for this problem.

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## SOLUTION This solution is **FREE** courtesy of BrainMass!

Apply the thin lens equation

1/s0 + 1/si = 1/f

where s0 is the distance measured from the object to the center of the lens. so s0 = +36 cm since it is placed to the left of the lens.

si is the distance measured from the lens to the image.

f is the focal length. f = +66 cm since the lens is convex and converging.

1/36 + 1/si = 1/66

1/si = 1/66 - 1/36

si = -79.2 cm

The negative sign means that the image is formed to the left side of the lens.

The magnification is

M = -si/s0 = -(-79.2)/36 = 2.2

The magnification is 2.2. It is positive, which indicates that an erected image is formed.

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