Heat and Thermodynamics: Monoatomic to diatomic
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Initially, a quantity of a mono atomic gas (cv=3R/2) occupies a rigid container with volume V=0.19m^3. The temperature and pressure are Ti=287k and Pi=108Kpa. The gas reacts completely with itself to form half the original moles of a diatomic gas (cp=5R/2). The reaction is exothermic and produces an amount of heat Q=36497 J which increases the final internal energy, what is the final temperature?
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Solution Summary
A gas reacts itself from mono atomic to diatomic, change in temperature is calculated.
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Initially, a quantity of a monatomic gas (cv=3R/2) occupies a rigid container with volume V=0.19m^3, The temperature and pressure are Ti=287k and Pi=108Kpa. The gas reacts completely with itself to form half the original moles of a diatomic gas (cp=5R/2). The reaction is exothermic and produces an amount of heat Q=36497 J which increases the final internal energy, what is the final ...
Purchase this Solution
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