Hi. I need some help with a conceptual question.
"A uniform 1-meter stick that is supported by a fulcrum at the 25-cm mark is in equilibrium when a 1-kg rock is suspended at the 0 cm end. Is the mass of the meter stick greater than, equal to, or less than the mass of the rock?"
I thought the answer would be that the mass of the whole meter stick must be greater than the rock, since 3/4 of the meter stick is balancing the rock plus the remaining 1/4 of the meter stick. (rock + 1/4 meter stick = 3/4 meter stick)
Can someone please explain this to me? Maybe plugging in some actual numbers would help.
See the attached figure...
<br>a) The center of mass of a uniform meter stick is at 0.5 m from one end. That is we can assume the mass of the rod to be concentrated at the 0.5 m point (a point ...
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