Three problems: Motion and equilibrium, Force, acceleration

16. The average speed of nitrogen molecule in air is about 6.70x10^2m/s, and its mass is 4.68x10^(-26) kg
a) If it takes 3.00x10^-13s for a nitrogen molecule to hit a wall and rebound with the same speed but opposite direction, what is the average acceleration of the molecule during this time interval
b)What average force does the molecule exert on the wall?
18. A bag of cement weigh 325N hangs in equilibrium from three wires as suggested of the picture below. Two of the wires make angle theta 1=60 degree, theta2=25 degree with the horizontal. Find the tension T1, T2 and T3 of the wires.

19. Based of the picture above to. A bag of cement weigh Fg hang in equilibrium from three wires as shown. Two of the wires make angles theta1, theta2 with the horizontal. Show that the tension on the left hand wire is
T1= (Fg.costheta2)/(sin(theta1+theta2))

1. The average acceleration of nitrogen molecule at the time of collision is calculated.
2. Tensions in the strings for a hanging block is calculated.
3. Expression of tension in a wire is derived.

... be able to solve most of the parallel problems on your ...3 It is directed radially It is directed radially r inwards ... the tires of the vehicle and Fig: Motion of a ...

... M2 g. As the mass is in equilibrium, net force on it must be zero. ...Problem 3 R. ... As the block has no motion perpendicular to the inclined plane, net force in that ...

... harmonic oscillator is given by x(t) = (0.5m)cos(πt/3) where t ... This set of multiple choice problems on circular and rotational motion, centre of ...

... Here are the solutions to these two problems! ... So the three equations with three unknowns are: ... frictional torque of 0.05m*N when the system is in motion what is ...

... This set of 23 problems includes problems on velocity, acceleration... sliding angle, the box is set into motion say by ... Distance traveled in 3 h at 80 km/h = 240 ...

... Hence, mg - 65.7sin42O = 0 or m = 65.7sin42O/9.81 = 4.5 kg Problem 36 : 9.8N 19.6N T2 T2 T1 ... Applying Newton's second law (F = ma) to the three masses we have ...

... As block A has no vertical motion, net vertical force... Substituting for T in (3) we get: aB = (98 2x33 ...Problem 2: The collar rotates with an angular speed ω ...

... Iα [It is the second law of motion applied to rotational motion (F = ma ... τ = 2.38 Nm Problem 3. ... Then for equilibrium (holding in level position) : Fd = 458.64 ...