Purchase Solution

Physics: Terminal velocity, time elapsed, distance fallen, equilibrium position

Not what you're looking for?

Ask Custom Question

See attached problems.

Find the terminal velocity, time elapsed and distance fallen, equilibrium position, effective spring constant, and angular frequency.

Attachments
Purchase this Solution
Solution Summary

The terminal velocity, time elapsed, distance fallen and equilibrium positions are analyzed. The effective spring constants are given. The solution provides good explanations and formulas, the problems are solved.

Purchase this Solution
Free BrainMass Quizzes
Basic Physics

This quiz will test your knowledge about basic Physics.

The Moon

Test your knowledge of moon phases and movement.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

View More Free Quizzes
Related BrainMass Solutions

  • Free Fall from a Moon Tower

    Given the distance fallen D = (0.5)(1.65)* t^2 (meters) ( V= 1.65 t) Downward Velocity (meters/sec) and the elapsed time is 0,1,2,3,...7 sec. Please see the attached file.

  • Displacement vs Time and Velocity vs Time

    Time elapsed between positions is .33 second. Step 4. The time of successive positions is: at release, 0 sec, position #1 at .33 sec, #2 at .66 sec, #3 at .99 sec, #4 at 1.32 sec and so on.

  • Average velocity

    The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time.

  • Harmonic Motion

    44197 Calculate the velocity acceleration and position of the cart. An air track cart attached to a spring completes one oscillation every 2.5 s. At t=0 the cart is released from rest at a distance of 15 cm from its equilibrium position.

  • Physics - Classical Mechanics - Motion

    (b) Distance covered = 0.5 x 293 = 146.52 m. (c) t = (w2 ?w1)/alpha = 0.052/2.73 x 10^ -3 = 19.04 s. The expert examines the magnitudes of a centripetal of a car. The speed, distance traveled and elapsed time is determined.

  • AP physics problem for the pressure cacluation

    Assuming the acceleration was constant; calculate the distance d below the surface at which the ocean liner reached this terminal velocity. The distance f.)

  • Physics Problems

    The most general equation for displacement is s = s0 + V0t + (1/2)at2 where s = displacement after time t s0 = initial displacement (location at t = 0) V0 = initial velocity (velocity at t = 0) t = elapsed time in seconds a = acceleration

  • velocity, acceleration, distance

    162707 velocity, acceleration, distance motion Hello I need help with the following Physics problems. 9. A train approaches a small town with a constant velocity of +28.6 m/s.

  • Current Electricity and Equivalent Resistance

    However, since the collisions are a random process, the time elapsed since the last collision for different electrons are different i.e. different electrons are moving with different velocities depending upon the time elapsed since its last collision

View More Related Solutions