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Mass under attractive force with angular momentum; determining energy and radius.

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A particle of mass m moves under as an attractive central force Kr^4 with angular momentum l. For what energy will the motion be circular, and what is the radius of the circle? Find the frequency of radial oscillations if the particle is given a small radial impulse.

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Solution Summary

A step by step solution of the mathematics involved to determine angular momentum, circular motion, and radius is given.

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For circular motion:
mv^2/r = Kr^4 .............(1)

and angular momentum,
l = mvr
v = l/mr ............(2)
Therefore, from equation (1) ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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