A 0.50-kg mass is attached to a spring with a spring constant of 20 N/m along a horizontal, frictionless surface. The object oscillates in simple harmonic motion and has a speed of 1.5 m/s at the equilibrium position. What is the total energy of the system?© BrainMass Inc. brainmass.com December 24, 2021, 10:23 pm ad1c9bdddf
SOLUTION This solution is FREE courtesy of BrainMass!
m = 0.5kg
k = 20 N/m
v = 1.5m/s
At the equilibrium place the spring is not stretched or compressed, hence the entire energy in the system is in the form of kinetic energy of the mass.
E = 1/2 m * v^2
Therefore, the total energy of the system is 0.5625 J.© BrainMass Inc. brainmass.com December 24, 2021, 10:23 pm ad1c9bdddf>