Purchase Solution

Self inductance of a coil

Not what you're looking for?

Ask Custom Question

A coil of 500 turns is wound on a wooden ring having a mean diameter of 8 cm and a cross sectional area of 1.5 cm^2. Assuming relative permeability of wood is 1, calculate the self-inductance of the coil and the emf induced in it when the direction of a DC current of 5A flowing in it is reversed in 0.2 sec?

Purchase this Solution
Solution Summary

It does not compute the answer, but gives relevant formulas and equations explaining how these can be used to compute the answer.

Purchase this Solution
Free BrainMass Quizzes
The Moon

Test your knowledge of moon phases and movement.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

Basic Physics

This quiz will test your knowledge about basic Physics.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

View More Free Quizzes
Related BrainMass Solutions

  • Mutual inductance and inductance of a transformer primary

    Perpendicular planes) When coil is wound from a wire, the self inductance of the coil is directly proportional to the square of the total number of turns (L = μ0N2A/l, where μ0 is permeability, N is total number of turns, A is area of cross section

  • Inductance of a Coil

    Magnitude of self induced emf = LdI/dt = 0.86 x 10^-3 x 12.5 = 10.75 x 10^-3 Volts or 10.75 mV The inductance of a coil is determined. A step by step solution provided.

  • Inductance of a short coil

    20236 Inductance of a short coil I have the inductance of the long coil which is L=( Meu (not)* N^2 * A ) / (D) A = Area , D = Length , N = number of turns in the coil I need to prove that for a short coil the inductance (L) is the following:

  • Electromagnetic Induction: Self and Mutual Inductance

    To derive and calculate self-inductance of a toroidal coil. 2 To calculate energy stored. 3 To calculate mutual-inductance. 4 To derive and calculate induced current.

  • Toroidal Solenoid

    It helps calculate the coil's self-inductance, calculate the self induced emf in the coil, and determine the direction of induced emf. A step by step solution provided.

  • Induced emf coils

    127832 Induced emf coils A coil with a self-inductance of 0.750 mH experiences a constant current buildup from zero to 10 amperes in 0.250 seconds. What is the induced emf during this interval?

  • Physics: mutual inductance

    Show that the mutual inductance between two coaxial coils separated by a distance z as in figure attatched, one of radius a and N_a turns, and the other of radius b << a and N_b turns is: pi*mu_0*N_a*N_b*a^2*b^2/[2(a^2 + z^2)^(3/2)] Calculate the

  • Rotating electromechanical system

    φ = KI Net flux through NS turns of the stator coil = ΦS = KISNS ......(4) Net flux through a coil is also given by: Φ = LI .........(5) Comparing (4) and (5) we get: Self inductance of stator coil = LSS = KNS Similarly,

  • What is the inductance of an inductor given:

    What is the inductance of an inductor given:: Air core 100 turns Cross-section area of core is 0.01 square meter Length is 0.1 meters Inductance of a short air core cylindrical coil in terms of geometric parameters:

View More Related Solutions