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    Inductance of a short coil

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    I have the inductance of the long coil which is
    L=( Meu (not)* N^2 * A ) / (D)
    A = Area , D = Length , N = number of turns in the coil

    I need to prove that for a short coil the inductance (L) is the following:
    L =[( Meu (not)* N^2 * A ) / (D)] * [ [{(D^2 - a^2)^(1/2)} - a ] / (D)] ]
    a = radius of the coil
    A = 3.14 a^2

    © BrainMass Inc. brainmass.com March 4, 2021, 5:57 pm ad1c9bdddf
    https://brainmass.com/physics/electric-magnetic-fields/inductance-short-coil-20236

    Solution Summary

    This solution is provided in a 2 page .pdf file and a .jpg image is attached as well to further understanding. It uses step-by-step equations for magnetic field and self induction to find the answer to the problem.

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