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    Solving pointing vectors

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    Light is directed on the surface of the non-conductive material at an angle of incidence of pi/6, just outside of this surface the intensity is 50(W/M^2). The EM wave is polarized in the plane of incidence.

    1. Find the E0 and B0 outside the material.
    2. Find the pointing vector outside the material.
    3. What is the intensity of light falling on the surface?

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    Solution Preview

    Intensity, I = 50 W/m^2

    1. Because,
    I = (1/2)*epsilon_o * Eo^2 * c

    epsilon_o = Permittivity of free space = 8.86*10^(-12) C^2/N.m^2

    c = speed of light = 3*10^8 m/s


    50 = ...

    Solution Summary

    The pointing vector of a given EM wave which is polarized in the plane of incidence is given.