# Magnetic Field Strength

A piece of copper wire has a resistance per unit length of 6.45E-3 omega/m. The wire is wound into a thin, flat coil of many turns that has a radius of 0.170 m. The ends of the wire are connected to a 12.0 V battery. Find the magnetic field strength at the center of the coil. Answer in T.

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#### Solution Preview

Because,

B = 10^(-7)*pi*N*I/r

r = radius = 0.170 m

I = V/R

<V = 12 Volt

R = resistance = 6.45*10^(-3)*l

where l is the length ...

#### Solution Summary

The answer is given step-by-step equationally.

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