Equipotential curves
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Hello,
The problem states:
V(x,y,z) = A(x^2 - 3y^2 + z^2)
E(vector) = -2Ax, 6Ay, -2Az
A = 640
the E field at a point (0,0, 0.250) = (0,0,-320)
It says:
In every plane parallel to the x-z plane, the equpotential contours are circles. What is the radius of the equipotential contour corresponding to V = 1280 V and y = 2.00 m?
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Solution Summary
The solution shows how to convert the potential equation to a canonical circle equation.
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Hello and thank you for posting your question to Brainmass!
Actually, the information regarding the electric field is not needed at all.
If the potential is ...
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