Two point charges lie on the x axis. A charge of + 6.2 micro C is at the origin, and a charge of -9.5 micro C is at x = 10.0 cm. What is the net electric field at
(a) x = -4.0 cm and at
(b) x = +4.0 cm?
The electric field is given by:
E = kq/r^2
To find the net electric field at each point we must sum up the effect of both charges on that point.
a) x = ...
This solution is comprised of a concise step by step solution of how to calculate the strength of an electric field at different positions relative to two different point charges.