Potential Energy & Energy Conservation - Springs

Related BrainMass Solutions

• Mechanics: Conservation of energy, falling mass on spring.

  Applying law of conservation of energy we get Loss in gravitational potential energy = gain in elastic potential energy gives mg(h + x) = (1/2) Kx2 where x is the compression in the spring gives 80*9.8(2.5 + 0.240) = (0.5) K*(0.240)2.

• Energy of a particle attached to 3 springs

  Energy in springs. Elastic potential and kinetic energy. Conservation of energy. Hooke's Law.

• box moving between two different springs

  cm Since there is no friction during the whole motion, we can apply for the conservation of energy.

• Springs and Slopes

  The key point of this problem is the conservation of energy.

• Acceleration of blood in vasculature; elevator springs energy

  However, the conservation of energy asserts that the energy required to break the car's fall is the same whether the springs are present or not. How, then, do the springs save lives?

• A Discussion On Compressed Springs And Spring Constants

  As the elastic potential energy stored in the spring compressed by L is given by U = ½ K L2 Using law of conservation of mechanical energy the velocity of projection v is given by Gain in kinetic energy = loss in elastic potential energy

• Spring constant problem: Work done, speed of block, maximum compression

  (in m) What you have here is an interesting problem in conservation of energy. What makes springs interesting is that the force required to stretch the spring is directly proportional to the distance it is stretched.

• System of springs: Energy stored in different springs

  578075 System of springs: Energy stored in different springs You can assume that air resistance and other frictional forces can be ignored in this question See attachment a) Define a datum for the gravitational potential energy of particle P.

• Oscillations: The spring with varying force constant

  This can be calculated using the conservation of energy as the total mechanical energy is conserved Elastic potential energy of the spring at one extreme = Elastic potential energy of the spring at other extreme Or (1/2)kA2 = (1/2) (2k)(-