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    Flow in a Pipe using Conservation of Mass

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    In your figure some data are missing like the angle of bent and the final area of cross-section.

    Hence, here I'm giving you the method that how to solve the problem.

    First by energy law:
    (p1-p2)/(rho*g) = (v2^2 - v1^2)/(2*g) + KL*v2^2/g .......(1)
    where, KL is the coefficient to calculate the loss due to:
    1. bend,
    2. contraction
    You can assume it's value around 0.7 ...

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