A shotputter throws the shot (mass = 7.3 kg) with an initial speed of 14m/s at a 40* angle to the horizontal. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.2 m above the ground.
For the vertical movement, the initial velocity of the shot is Vy when it is thrown upward. When it reaches the highest point, the vertical velocity is zero.
Vy=V*sin(theta)=14*sin(40 degree)= 9 ...
This solution calculates the horizontal distance traveled by a shot with a given mass, speed, angle and height.