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At what speed would your 4.98 m long car fit in the 4.19 m

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Part 1

When parked, your car is 4.98 m long. Unfortunately, your garage is only 4.19 m long. How fast would your car have to be moving (in c) for an observer on the ground to find your car shorter than your garage? Do not enter unit.

Part 2

When you are driving at this speed, how long is your garage, as measured in the car's frame of reference?

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(1) Let the speed of the car be v

The apparent length of x = x * sqrt[1 - (v/c)^2] ...

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