"A car accelerates from rest and travels for 4.98 s with a uniform acceleration of +1.50 m/s^2. The driver then applies the brakes, causing a uniform acceleration of -1.99 m/s^2. If the brakes are applied for 3.06s, how fast is the car going at the end of the braking period? And how far has the car gone?"
Solution. By the hypothesis, the initial speed of the car is v0=0, and the uniform acceleration a1=1.5m/s^2. So, after t1=4.98s, the speed of the car V is
The direction of V is the same as the acceleration, say "right".
Then, the driver applies the brakes, causing a uniform acceleration of a2=-1.99m/s^. The "-" means decreasing ...
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