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Finding Acceleration

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Hi, I need some assistance completing the following questions:

A car starting from rest moves with a constant acceleration of 2 m/s^2 for 10 s, then travels with constant speed for another 10 s, and then finally slows to a stop with constant acceleration of -2 m/s^2. How far does it travel?
a. 400 m
b. 100 m
c. 500 m
d. 300 m
e. 200 m

A car with good tires on a dry road can accelerate at about -4.5 m/s^2 when braking. If the car is traveling at 22.0 m/s when the brakes are applied, how far does the car travel before it slows to 10 m/s?
a. 85.3 m
b. 66.7 m
c. 53.8 m
d. 42.7 m

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Solution Summary

This solution is comprised of a detailed, step by step response which illustrates how to solve both of these physics-based questions. In order to view the response, a Word document file needs to be opened.

Solution Preview

Please refer to the attachment.

For the first question, the answer is A.

How to get this answer?
We consider three time intervals

1) [0,10s]
In this interval, a car ...

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
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