# Simple Harmonic Motion in an Oscillator

The position of a simple harmonic oscillator is given by x(t)=(0.5m)cos((pi/3)t) where t is in seconds. What is the maximum velocity of this oscillator?

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#### Solution Preview

The general equation for position vs time of SHM is X = Xmax cos w t in whicih w is the angular frequency of the motion. This equation

shows that ...

#### Solution Summary

The solution calculates the maximum velocity of the oscillator.

String tensions for maximum and minimum motion of bungee cord

Traveling waves are set up in a pair of long strings by a simple harmonic oscillator. The strings have identical mass densities of 5.1 grams/meter. Both strings terminate at a short bungee cord attached to a wall. The harmonic oscillator is attached to the other ends of the strings in such a way that one string is 5.4 meters longer than the other. If the oscillator has frequency 97 Hz:

Give at least two string tensions which will produce the minimum motion of the bungee cord.

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