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    The position of a mass oscillating on a spring is given by
    X= 7.8 cm cos [2 pi t / (0.68 s) ]

    a. What is the frequency of this motion?

    b. When is the mass first at the position x= -7.8cm

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    Solution Preview

    a) angular velocity = w =2pi /T= 2pi /0.68
    Therefore T=0.68 ...

    Solution Summary

    The expert calculates frequency of oscillatory motion and the time when the mass is first at the position x= -7.8cm.