Purchase Solution

geodesic

Not what you're looking for?

Ask Custom Question

See attached file for full problem description.

Show that the geodesic on the surface of a right circular cylinder is a segment of a helix.

Notes: when it syas "show" the path, use the techniques oof calculus of variations to find an equation y = f(x), z = f(x,y) for the path, then explain how this function is the type of path desired.

Attachments
Purchase this Solution
Solution Summary

It shows that the geodesic on the surface of a right circular cylinder is a segment of a helix. The solution is detailed and has '5/5' rating.

Solution Preview

Please see the attached file.

Show that the geodesic on the surface of a right circular cylinder is a segment of a helix.

The element of distance along the surface of a cylinder is
(1)

In cylindrical coordinates ...

Purchase this Solution
Free BrainMass Quizzes
Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

Basic Physics

This quiz will test your knowledge about basic Physics.

The Moon

Test your knowledge of moon phases and movement.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

View More Free Quizzes
Related BrainMass Solutions

  • Christoffel symbols and Geodesic

    577054 Christoffel Symbols and Geodesic In cylindrical coordinates (ds)^2=(dp)^2+p^2(d(thi))+(dz)^2.

  • Grammar: Misplaced Modifiers

    Today, to most people, Fuller is known as the inventor of the geodesic dome. 7. The geodesic dome, which Fuller developed in the late 1940s, is a lightweight and economical spherical structure. 8.

  • Geodesics of a Parabolic Cylinder

    This solution derives the general form of the geodesic equation for a 2D surface and derive the geodesic equations for the case of a parabolic cylinder.

  • Light signals and time differences in Schwarzchild geometry

    : ds^2 = c^2(1-2m/r)dt^2 - (1-2m/r)^(-1)dr^2 - r^2 d theta^2 - r^2sin^2(theta)d phi^2 where m = MG/c^2 You know that in a flat space-time the trajectory of a photon is such that ds^2 = 0 on the trajectory (such a trajectory is called a null geodesic

  • Statistical Distance vs. Actual Distance

    And we know that on a sphere the closest distance between two points is the geodesic arc between the two vectors as seen in the figure to the right: On a unit sphere this is simply the angle between the vectors.

  • Biography of a Mathematician: Carl Friedrich Gauss

    Ø He also discovered heliotrope by contemplating sun rays and described the concepts involved in non-Euclidean geometry as well as Gaussian curvatures, which is concerned to the geodesic survey.

View More Related Solutions