# Question about Electrical Energy Conversion

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A 100 kVA, 60 Hz, 7200/480 V, single-phase transformer has the following parameters (all expressed in ohms):

RHV = 3.06

RLV = 0.014

XHV = 6.05

XLV = 0.027

Xm,HV = 17,809

Re,HV = 71,400

The transformer supplies a load that draws rated current at 0.75 power factor lagging at 480 V at the load. Sketch the approximate equivalent circuit for this transformer, and determine:

a. the input voltage

b. the efficiency

c. the percent voltage regulation

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##### Solution Summary

The solution contains two sketches for part (a) and calculations and explanations. The solution is 325 words.

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1. Equivalent circuit for transformer:

Where: R1=RHV =3.06 Ohm, X1 = XHV = 6.05 Ohm

(Voltage Ratio k=E1/E2 = 7200/480= 15)

R2' = (k*k)*RLV = (15*15)* 0.014 = 3.15 Ohm

X2' = (k*k)*XLV = (15*15)* 0.027 = 6.075 Ohm

Re = Re,HV=71400 Ohm, Xm = Xm,HV=17809 Ohm

Since Re and Xm is so large, they can be ignored during the calculation. The equivalent circuit of transformer can be simplified as attached.

2. The input voltage

Since the transformer ...

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