See attached file for full problem description.
2. In this circuit, the current through bulb A is 0.20 A, while that through bulb D is 0.35 A. All bulbs are identical. (A) For the sake of argument, let us consider only nodes where three or more wires come together. (We are stating this condition since some electrical engineers would arge that there is a node between bulbs A and B, even though only two wires are connected at the "node".) How many such nodes are in this circuit? (B) Find the currents through bulbs B and C, as well as the total current supplied by the battery.
3. In both circuits shown below, the same current is supplied by the battery. The crooked lines represent nichrome wire, whose measured lengths are indicated. How long should the wire be in circuit "B"? Explain how you know.
Please see attached file.
1. The equivalent circuit can be drawn as follows :
0.5A RA 0.15A
Bulbs A and B are in series. Therefore, the current through them will be same. Hence, current through bulb B = 0.15 A.
The current through bulb C can be found by using Kirchhoff's current rule.
Current through bulb C = Total current supplied by the battery - Current through bulb A = 0.5 - 0.15 = 0.35 A. ...
This solution determines the current through bulbs and also length of wires using equivalent circuits and application of Kirchoff's Laws.