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# Electric field of Plastic Pipes

A plastic pipe has an inner radius of a = 31.00 cm and an outer radius of b = 68.00 cm. Electric charge is uniformly distributed over the region a < r < b. The charge density in this region is 42.00 C/m3. Calculate the magnitude of the electric field at r = 0.29 m.
Calculate the magnitude of the electric field at r = 0.57 m. Calculate the magnitude of the electric field at r = 1.73 m.

I thought if I did E= lambda/2*pi*Eo*r, and placed the r asked I can solve this. But that was wrong. Why is this wrong?

#### Solution Preview

A plastic pipe has an inner radius of a = 31.00 cm and an outer radius of b = 68.00 cm. Electric charge is uniformly distributed over the region a < r < b. The charge density in this region is 42.00 C/m3. Calculate the magnitude of the electric field at r = 0.29 m.
Calculate the magnitude of the electric field at r = 0.57 m. Calculate the magnitude of the electric field at r = 1.73 m.

I thought if I did E= lambda/2*pi*Eo*r, and placed the r asked I can solve this. But that was wrong. Why is this wrong?