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Circuits - Charge and Voltage

A potential difference of 750 V is applied across two capacitors of capacitance 5 uF and 10 uF in series. Find the charge on each capacitor and voltage across each.

Solution Preview

First find equivalent capacitance for series capacitors (Ce):

1/C = 1/C1 + 1/C2 = 1/5e-6 + 1/10e-6= 300,000 (1/F)
Ce = 3.33e-6 F = 3.33uF

Now the charge ...

Solution Summary

This solution is provided in 135 words. It calculates equivalent capacitance in order to determine the voltage of the capacitors.