Explore BrainMass

# Capacitance: Parallel plate capacitor, series and parallel combinations, switch for a given charging potential

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

Please place step by step solutions and answers on separate piece of paper and give answer please. Draw pictures if needed. PLEASE DO all questions, again show all math, diagrams, etc. and only first 5 problems

1. Figure 25-19 shows plots of charge versus potential difference for three parallel-plate capacitors...

https://brainmass.com/physics/capacitors/43089

#### Solution Preview

Exercises:

1. Use the relation for a parallel plate capacitor C proportional to A/d A is the area of a single plate and d is the distance between the plates. Also use the relation C = Q/V or Q= CV. Then you can see in this C is the slope of the graph of Q(V) vs V. The larger the value of C the steeper the slope of this graph. Then for the correlation 1=b, 2=a, and 3=c.

2. To determine if a capacitor is in parallel look to see if the wires attaching can be removed and replaced with a single wire and twice the capacitive area. Are the wires common to a junction point and if so the capacitors are in parallel. Configuration a is a series, configuration b is in parallel, and configuration c) is a combination.

3. The configuration is a set of 3 capacitors in series . The potential difference for the series combination is Vbattery = V1 + V2 + V3 but here each ...

#### Solution Summary

The solutions provide good explanations for the answers to the problems.

\$2.49