To protect his food from hungry bears, a boy scout raises his food pack with a rope that is thrown over a tree limb at height h above his hands. He walks away from the vertical rope with a constant velocity, vboy, holding the free end of the rope in his hands. a) Show that the speed v of the food pack is given by x(x^2+h^2)^(-1/2) vboy where x is the distance he has walked away from the vertical rope. b) Show that the acceleration a to the food pack is h^2(x^2+h^2)^(-3/2)v^2boy. c)What values do the acceleration a and velocity v have shortly after he leaves the point under the pack (x=0)? d) What values do the pack's velocity and acceleration approach as the distance x continues to increase?

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Q: To protect his food from hungry bears, a boy scout raises his food pack with a rope that is thrown over a tree limb at height h above his hands. He walks away from the vertical rope with a constant velocity,vboy, holding the free end of the rope in his hands. a) Show that the ...

Solution Summary

The expert analyzes the velocity and acceleration of a pack.

...Acceleration is the rate of change of velocity over time ... don't instantly go from one velocity to another, they must accelerate to reach those velocities. ...

... ignoring the negative sign as acceleration is positive ... however, a raindrop can never reach this velocity. ... that the raindrop never reaches such high velocities. ...