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The radius of the Earth is R. At what distance above the Earth's surface will the acceleration of gravity be 4.9 m/s2 ? [Hint: Compute the distance, as a multiple of R, at which the acceleration due to gravity is half its surface value. Then subtract 1 from that value (because the problem asks "above the Earth's surface" ... not the distance from the center of the Earth).]
Please provide detailed explanation and reflect your work with units.

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Hi,

Using the Newton's law of universal gravitation formula, we have:

F = G*m1*m2 / r^2

Where:
F = gravitational force
G = gravitational constant = 6.67 x 10^-11 Nm^2/kg^2
m1 = mass 1
m2 = mass 2
r = ...

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