Problem # 9 - The semicircular disk having a mass of 10 kg is rotating at  = 4 rad/s at the instant  = 60 . If the coefficient of static friction at A is  s = 0.5, determine if the disk slips at this instant.

This is a complex problem and we solve it in 4 stages:
1. Find the center of mass and the moment of inertia
2. Assume no slipping and find angular acceleration
3. Find the acceleration of the center of mass
4. Find the friction and normal force at A and see whether the assumption of no slipping holds.

We are given ω = 0.4 rad/s, θ = 60°, R= 0.4 m.
Since the mass of the semicircle is irrelevant we do not use it, and just write "M" in the formulae. All Calculations are done in SI units (kg, s, m).

1.
The center of mass may be given in your book(s) or lecture notes. However, just in case, you can find its derivation on web page http://members.tripod.com/arilizi/CM_OF_A_SEMI_CIRCLE.htm
The ...

Solution Summary

The solution determines the disk slip at this instant.

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T= -k*theta The constant of proportionality k is called the "torsional

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See attached file for full problem description.
Note for clarification. The initial position refers to the puck is: (x = -.5R, y = 0)

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Please see the attachment for proper formatting and diagrams.
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a. 0.667 rad/s
b. 1.06 rad/s
c. 0.888 rad/s
d. 1.74 rad/s
e. 2.31 rad/s
2. The stepped disk

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Ans clue- If A w

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c. What is the impact on the end date of the project if act

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a. Which would you choose to yield the best p