Purchase Solution

# Circular Launch (Centripetal Acceleration)

Not what you're looking for?

A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the ball has a centripetal acceleration of magnitude 2g.

How far from the bottom of the chute does the ball land? (Your answer for the distance the ball travels from the end of the chute should contain R.)

##### Solution Summary

We start this solution by solving for the velocity of ball before free fall in the horizontal direction: v^2/R = 2*g => v = sqrt(2*g*R). Full calculations and answer for distance travelled from chute are included.

##### Solution Preview

Because, before free fall if velocity of ball is v (horizontal)
v^2/R = 2*g
=> v = sqrt(2*g*R)

In ...

Solution provided by:
###### Education
• MSc , Pune University, India
• PhD (IP), Pune University, India
###### Recent Feedback
• " In question 2, you incorrectly add in the \$3.00 dividend that was just paid to determine the value of the stock price using the dividend discount model. In question 4 response, it should have also been recognized that dividend discount models are not useful if any of the parameters used in the model are inaccurate. "
• "feedback: fail to recognize the operating cash flow will not begin until the end of year 3."
• "Great thanks"
• "Perfect solution..thank you"

##### Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

##### The Moon

Test your knowledge of moon phases and movement.

##### Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

##### Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.