1. Assume you are walking in front of a motion sensor that graphs the distance you have walked (y axis) against time (x axis). Describe the motion that you need to make to produce the following graphs:

a) Line with a positive slope.
b) Line with steeper positive slope.
c) Line with negative slope.
d) Line with zero slope.
e) A Parabola

2. An object is released (from rest) at the top of an inclined plane. After time t, the object has moved a distance d down an incline. What is its acceleration?

3. Show that the acceleration of a solid cylinder rolling down an incline that makes an angle θ with the horizontal is given by a=2/3g sin θ. Use the principle of conservation of mechanical energy.

4. If m1g-T1=m1a, and T2-m2g=m2a, and (T1-T2)R=Iα

Solve these equations simultaneously to arrive at the following equation: (m1-m2)g=(m1+m2+( I/R^2))a

5. If m1g-T1=m1a, and T2=m2a, and (T1-T2)R=Iα

Solve these equations simultaneously to arrive at the following equation: m1g=(m1+m2+( I/R^2))a

Solution Summary

This solution provides steps necessary to determine the acceleration of the object rolling down an incline.

Linear velocity of cylinders when rolling down an incline. ... The acceleration of gravity is 9.8 m/s2 : Find the ... When the first object reaches the bottom, what is ...

... mass M. Released from rest, the two objects remain in ... as the block slides and the cylinder rolls down the ... Find a, the acceleration down the plane of the center ...

... path and hence the corresponding centripetal acceleration is always ... is no way to tell which object goes farther, because the radii of the objects aren't ...

... You apply the same force to two objects. ... 7 Using Newtons law since there is no acceleration, we see. ... 9 For object 1 we get F F = Ma1 ⇒ a1 = M and for object 2 ...

... Mass of an object remains the same always at any ... Thus, weight = mass x acceleration due to gravity. ... Since the ball is only rolling without slipping, the energy ...

... down a ramp that is at a 30° incline. ... out of a child's pocket and rolls 5 meters ... the following statements concerning the object's acceleration is necessarily ...

...Acceleration a = Force/Mass = T/m = 0.9g = 0.9 x 9.8 ... As angular momentum of an object about a given axis is ... mass m = 10kg and radius r = 0.4m is rolled down a ...

... is no slipping and the body have pure rolling, the point ... or the line) of contact of the object with the ... the body is I then the angular acceleration about this ...

... spine muscles and transverse abdominis is the rolling side bridge ... Spine tion on lumbar acceleration. ... potential energy is calculated form, objects have potential ...