# Real Analysis of Upper Bounds

Prove that if a is an upper bound for A and if a is also an element of A, then it must be that a=sup A

Â© BrainMass Inc. brainmass.com February 24, 2021, 2:30 pm ad1c9bdddfhttps://brainmass.com/math/real-analysis/real-analysis-upper-bounds-25325

#### Solution Preview

Proof. Since a is an upper bound for A, namely, for every element x in A, we have ...

#### Solution Summary

This is a proof regarding the upper bound and the supremum.

$2.19