Real Analysis of Upper Bounds
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Prove that if a is an upper bound for A and if a is also an element of A, then it must be that a=sup A© BrainMass Inc. brainmass.com March 6, 2023, 1:26 pm ad1c9bdddf
Proof. Since a is an upper bound for A, namely, for every element x in A, we have ...
This is a proof regarding the upper bound and the supremum.