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    Real Analysis of Upper Bounds

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    Prove that if a is an upper bound for A and if a is also an element of A, then it must be that a=sup A

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    https://brainmass.com/math/real-analysis/real-analysis-upper-bounds-25325

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    Proof. Since a is an upper bound for A, namely, for every element x in A, we have ...

    Solution Summary

    This is a proof regarding the upper bound and the supremum.

    $2.19

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