Probability and the Binomial Distribution
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A manufacturing company has 10 machines in continous operation during a workday. The probability that an individual machine will break down during the day is .10. Determine the probability that during any given day 3 machines will break down.
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Let X be the number of machines that break down. X has the binomial distribution with n = 10 trials and success probability p = 0.1
In general, if X has the binomial distribution with n trials and a success probability of p then
P[X = x] = n!/(x!(n-x)!) * p^x * (1-p)^(n-x)
for values of x = 0, 1, 2, ..., n
P[X = x] = ...
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