1) f(x)=3x(2x-1). f(-1)=
A)7 (B)11 (C)-6 (D) 9
3)The line 6x + 9y=8 has slope
A) -2/3 (B)-6 (C) 4/3 (D) 9
4)Select the line parallel to 6x +14y =20
A) 3x-7y=15(B) 7x-3y=8 (C) y=20/6x+14 (D)y= -3/7x+11/7
5) A revenue function is R(x)=28x and a cost function is C(x)=-15x+344. The break-even point is
A)(224, 11) (B)(8, 244) (C) (15, 420) (D) (26.5, 741)
6)An item cost $900, has a scrap value of $50 and a useful life of five years. The linear equation relating book value and number of years is
A) BV=-50x + 850 (B) BV=-50x + 900 (C) BV =-170x+ 850 (D) BV =-170x +900
7) The supply equation is y=28x + 2025 and the demand equation is y=-17x+6120. The equilibrium demand is
A) 45 (B) 4573 (C) 2025 (D)91
8)One printing shop charge $5 plus $0.02 per page and a second shop charges $7 plus $0.015 per page. If _________ pages are printed the total cost is less for the first printing shop.
A) less than 1500 (B) less than 2100 (C) less than 400 (D) less than 900
10) The system below has _____solutions
A) none (B) one (C)three (4) infinite
11)The solution to the system of equation below is
A) (1,1,6) (B) (1,3,5) (C)(4,-1,4)(D)(2,-1,3)
12) An artist is painting a supply of small painting to sell at an art festival. He can paint three landscapes per hour and two seascapes. He can frame five paintings per hour. He has 50 hours available for painting and 25 hours available for framing. How many of each type of painting should he paint and frame in order to maximize the landscapes and $30 each for the seascapes.
A). Maximum value =$4,375 for 75 landscapes and 50 seascapes
B) Maximum value =$3,375 for 75 landscapes and 50 seascapes
C) Maximum value =$4,375 for 50 landscapes and 75 seascapes
D) Maximum value =$3,375 for 50 landscapes and 75 seascapes
Linear Programming, Equations of Lines and Word Problems are investigated. The solution is detailed and well presented.