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Linear Algebra: Eigenvalues

Find eigenvalues and eigenvectors of the matrix
A=(2 1
9 2)

By transforming the matrix in the basis of eigenvectors, show explictly that the matrix can diagonalized in the eigenvector basis.

Solution Preview

The definition of an eigenvalue is:

AX = LX where L is the eigenvalue (lambda)

Which can be rewritten:

(LI-A)X = 0, where I is the identity matrix.

So, that brings us to the characteristic polynomial in our 5 line review:

c(x) = det(xI - A)

The eigenvalues are the roots of this ...

Solution Summary

Eigenvalues of a matrix are found. Diagonalization is shown.