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sketch the curve for y = sin(X) between x = 0 and x = 2pi, then find the total area enclosed by the curve y = sin x and the X axis between x = 0 and x = 1.7pi
I have got the sketch a graph bit sorted i just can't work out the rest. if you could provide full workings and method that would be great
∫ (5x^2 + sqrt(x) - 4/x^2) dx

∫ [cos(x/2) - sin(3x/2)] dx

∫ s/sqrt(s^2 + 4) ds (upper coordinate is 5 lower coordinate is 1)

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