Suppose f(b) = f'(b) = 0 and a < b. Show that if f''(x) ≥ 0 for x є [a,b], then f(x) ≥ 0 for x є [a,b].© BrainMass Inc. brainmass.com October 9, 2019, 8:23 pm ad1c9bdddf
First we note that if f''(x) ≥ 0 for x є [a,b] then f'(x) is NON-DECREASING for x є [a,b] ...
A differentiability proof is provided. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.