Suppose f(b) = f'(b) = 0 and a < b. Show that if f''(x) ≥ 0 for x Є [a,b], then f(x) ≥ 0 for x Є [a,b].
First we note that if f''(x) ≥ 0 for x Є [a,b] then f'(x) is NON-DECREASING for x Є ...
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