Where is the graph of 1/4x^4 - 2x^2 concave down?
keywords: concave-down, concave-up, up, second-derivatives, second, derivatives
Hi, here is the solution
y= (1/4) x^4 -2x^2
dy/dx = (1/4)4x^3 -4x
dy/dx = x^3 -4x
Make dy/dx =0 , to find the critical points,
x=0 (or) x^2-4 =0
x=0 and x= ...
Intervals where a curve is concave down are found. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.